Question

Three angles of a seven sided polygon are ${132}^{\circ }$each and the remaining four angles are equal. Find the value of each equal angle.

• A. ${125}^{\circ }$
• B. ${156}^{\circ }$
• C. ${126}^{\circ }$
• D. ${130}^{\circ }$

Answer 1

The correct option is C ${126}^{\circ }$

Three angles of a seven sided polygon are ${132}^o$ each and the remaining four angles are equal. Let each equal angle is = $x^o$

Sum of total angle = $3\times {132}^o+4\times x^o$

Sum of total interior angles of any polygon = ${180}^o(n-2)$ $={180}^o(7-2)={180}^o\times 5={900}^o$

$3\times {132}^o+4\times x^o={900}^o$

$4x^o={504}^o$

$x^o={126}^o$

Remaining four angles are ${126}^o$