1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

# Three are n points in a plane, no three being collinear except m of them which are collinear. The number of triangles that can be drawn with their vertices at three of the given points is

A
nmC3
No worries! Weâ€˜ve got your back. Try BYJUâ€˜S free classes today!
B
nC3mC3
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
nC3m
No worries! Weâ€˜ve got your back. Try BYJUâ€˜S free classes today!
D
None of these
No worries! Weâ€˜ve got your back. Try BYJUâ€˜S free classes today!
Open in App
Solution

## The correct option is B nC3−mC3Given n points the number of triangles that can be drawn by joining any three non - collinear points nC3 out of this mC3 is to be subtracted as m points are collinear and no triangle is possible within the m points.

Suggest Corrections
0
Join BYJU'S Learning Program
Related Videos
Geometric Applications of PNC
QUANTITATIVE APTITUDE
Watch in App
Join BYJU'S Learning Program