Question

Three arrangements are shown for the complex, $\left[Co\right(en\left)\right(N{H}_3{)}_{2}B{r}_2{]}^{+}$. Which one is the wrong statement?

• A. I and II are geometrical isomers.
• B. II and III are optical isomers.
• C. I and III are optical isomers.
• D. II and III are geometrical isomers.

Answer 1

The correct option is B II and III are optical isomers.

I and II are geometrical isomers. I is cis as two $Br$ atoms are adjacent to each other. II is trans as two $Br$ atoms are opposite to each other.

II and III are geometrical isomers. II is trans as two $Br$ atoms are opposite to each other. III is cis as two $Br$ atoms are adjacent to each other.

I and III are optical isomers. They are non-superimposable mirror images of each other.