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Question

Three arrangements are shown for the complex [CoBr2(NH3)2(en)]. Which one is wrong statement?

146158_8c412f3fb2c04edfb481cf1e7ce23a71.png

A
I and II are geometrical isomers
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B
II and III are optically active isomers
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C
I and III are optically active isomers
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D
II and III are geometrical isomers
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Solution

The correct option is B II and III are optically active isomers
(A) I and II are geometrical isomers.
In I. two bromine atoms are cis to each other. It is cis iomer.
In II. two bromine atoms are trans to each other. It is trans isomer.
Thus statement A is correct statement.
(B)II and III are geometrical isomers as II is trans while III is cis of the given complex.
They ae not optical isomers.
Hence, statement B is incorrect.
(C) I and III are optically active isomers. They are non superimposable mirror images of each other.
Thus statement C is correct statement.
(D)II and III are geometrical isomers
In II. two bromine atoms are trans to each other. It is trans isomer.
In III. two bromine atoms are cis to each other. It is cis iomer.
Thus statement D is correct statement.

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