Three arrangements of spring-mass system are shown in figures (A), (B) and (C), If T1, T2 and T3 represent the respective periods of oscillation, then correct relation is :
A
T1>T2>T3
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B
T3>T2>T1
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C
T2>T1>T3
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D
T2>T3>T1
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Solution
The correct option is BT2>T1>T3
The restoring force F=−kx, where x is the elongation or compressed length.
Now for the figure A, when the mass m moves a distance x downwards, the spring is also elongated with the same distance x. P.E.=12kx2So the restoring force for fig A is F=−kx
For the figure B, when the mass m moves a distance x downwards, the spring is elongated by a distance x2. P.E.=12k(x/2)2=12(k4)x2. So the restoring force for fig B is F=−(k4)x.
In the similar way, for fig C, the restoring force is F=−(4k)x.
∴ for fig A, B, C the new spring constant are k,k4,4k respectively.