Question

Three atoms of elements with $Z=15,Z=16,Z=17$ are considered. Which one is the extraordinary stability of one arrangement?

• A. $Z=15$
• B. $Z=16$
• C. $Z=17$
• D. None of the above

Answer 1

The correct option is A $Z=15$

The electronic configuration of an atom with Z = 15 is: $\left[Ne\right]3s^{2}3p^3$

The electronic configuration of an atom with Z = 16 is: $\left[Ne\right]3s^{2}3p^4$

The electronic configuration of an atom with Z = 17 is: $\left[Ne\right]3s^{2}3p^5$

The electronic configuration of an atom with Z = 15 is most stable as the $3p^3$ is half filled.