Question

Three balanced coins are tossed simultaneously. If $X$ denotes the number of heads, find probability distribution of $X$.

Answer 1

$x=1,y=\frac{2}{3}$

$(1,\frac{2}{3})$ is point of trisection

In this case there are 8 possible outcomes as 2 on each

$\therefore 2\times 2\times 2=8$ on there

Outcome	HHH	HHT	HTH	THH	HTT	THT	TTH	TTT
No. of Heads	3	2	2	2	1	1	1	0

$x\to$ No. of heads

$X$	0	1	2	3
$P\left(X\right)$$	$\frac{1}{8}$	$\frac{3}{8}$	$\frac{3}{8}$	$\frac{1}{8}$