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Standard VIII

Physics

Archimedes Principle

Three beakers...

Question

Three beakers 1, 2 and 3 of different shapes are kept on a horizontal table and filled with water up to the same height h. If the pressure at the base of beakers are $P_{1}$ , $P_{2}$ and $P_{3}$ respectively, which of the following is the correct relation between them?

P_{1} > P_{2} > P_{3}

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P_{1} < P_{2} < P_{3}

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P_{1} = P_{2} = P_{3}

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P_{1} > P_{2} < P_{3}

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Solution

The correct option is C $P_{1} = P_{2} = P_{3}$
The pressure on the surface of the liquid in the beakers is same and equal to atmospheric pressure. The pressure increases with depth according to the formula $P = ρ g h$ , where $ρ$ is density of the liquid and g is acceleration due to gravity. Since all the beakers contain water up to the same height, $P_{1} = P_{2} = P_{3}$ .

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Three beakers 1, 2 and 3 of different shapes are kept on a horizontal table and filled with water up to the same height h. If the pressure at the base of beakers are P1, P2 and P3 respectively, which of the following is the correct relation between them?

Three beakers 1, 2 and 3 of different shapes are kept on a horizontal table and filled with water up to the same height h. If the pressure at the base of beakers are $P_{1}$ , $P_{2}$ and $P_{3}$ respectively, which of the following is the correct relation between them?