Three black bodies are such that the maximum intensity of their wavelength are in the ratio - m 1- - m 2- - m 3-1-210-5-30-5- Which of these is true for their temperature- A- T 1- T 3- T 2B- T 1- T 2- T 3C- T 3- T 2- T 1D- T 3- T 1- T 2

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Blackbody Radiation

Three black b...

Question

Three black bodies are such that the maximum intensity of their wavelength are in the ratio $λ_{m_{1}} : λ_{m_{2}} : λ_{m_{3}} = 1 : (21)^{0.5} : (3)^{0.5}$ .
Which of these is true for their temperature?

T_{1} > T_{3} > T_{2}

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T_{1} > T_{2} > T_{3}

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T_{3} > T_{2} > T_{1}

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T_{3} > T_{1} > T_{2}

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Solution

The correct option is A $T_{1} > T_{3} > T_{2}$
The wavelength of maximum intensity radiation decreases with the increase in the temperature.
$λ_{m 1} : λ_{m 2} : λ_{m 3} = 1 : (21)^{1 / 2} : (3)^{1 / 2}$
So, $λ_{m 2} > λ_{m 3} > λ_{m 1}$
Thus, $T_{1} > T_{3} > T_{2}$

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Blackbody Radiation

Standard XII Chemistry

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Three black bodies are such that the maximum intensity of their wavelength are in the ratio λm1:λm2:λm3=1:(21)0.5:(3)0.5. Which of these is true for their temperature?

The correct option is A T1>T3>T2The wavelength of maximum intensity radiation decreases with the increase in the temperature. λm1:λm2:λm3=1:(21)1/2:(3)1/2 So, λm2>λm3>λm1 Thus, T1>T3>T2

Three black bodies are such that the maximum intensity of their wavelength are in the ratio $λ_{m_{1}} : λ_{m_{2}} : λ_{m_{3}} = 1 : (21)^{0.5} : (3)^{0.5}$ .
Which of these is true for their temperature?

The correct option is A $T_{1} > T_{3} > T_{2}$
The wavelength of maximum intensity radiation decreases with the increase in the temperature.
$λ_{m 1} : λ_{m 2} : λ_{m 3} = 1 : (21)^{1 / 2} : (3)^{1 / 2}$
So, $λ_{m 2} > λ_{m 3} > λ_{m 1}$
Thus, $T_{1} > T_{3} > T_{2}$