Question

Three black bodies are such that the maximum intensity of their wavelength are in the ratio ${\lambda }_{m_1}:{\lambda }_{m_2}:{\lambda }_{m_3}=1:(21{)}^{0.5}:(3{)}^{0.5}$.
Which of these is true for their temperature?

• A. $T_3>T_2>T_1$
• B. $T_1>T_3>T_2$
• C. $T_1>T_2>T_3$
• D. $T_3>T_1>T_2$

Answer 1

The correct option is B $T_1>T_3>T_2$

The wavelength of maximum intensity radiation decreases with the increase in the temperature.
${\lambda }_{m1}:{\lambda }_{m2}:{\lambda }_{m3}=1:(21{)}^{1/2}:(3{)}^{1/2}$
So, ${\lambda }_{m2}>{\lambda }_{m3}>{\lambda }_{m1}$
Thus, $T_1>T_3>T_2$