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Question

Three block are tied together as shown in the figure. They are lying on a horizontal frictionless table. These are pulled to the right with $T_{3} = 12 N$ force. If $m_{1} = 1 k g, m_{2} = 2 k g, m_{3} = 3 k g$ , the tension $T_{1}$ in the string is ?

A

3 N

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B

12 N

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C

2 N

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D

1 N

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Solution

The correct option is A 2 N
Here,
$m_{1} = 1 m_{2} = 2 m_{3} = 3$
From FBD of systam
$T_{3} = (m_{1} + m_{2} + m_{3}) a = 12$
$a = 2 m / s^{2}$
From FBD of $m_{1} + m_{2}$
$T_{1} = T_{3} - (m_{3} + m_{2}) a = 12 - 5 \times 2 = 2$
Option $C$ is the correct answer

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