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Question

Three blocks 1, 2, & 3 rest on a horizontal frictionless surface, as shown. Each block has a mass m and the blocks are connected by massless strings. Block 3 is pulled to the right by a force F. The resultant force on block 2 is:
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A
Zero
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B
(1/3)F
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C
(1/2)F
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D
(2/3)F
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Solution

The correct option is B (1/3)F
According to the constraint of the system, all the three blocks will move with the same acceleration given by,
a=F/(3m)
Now, net force on second block will be equal to it's mass times acceleration.
Feq2=ma=m(F/3m)
Feq2=F/3

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