Three blocks 1, 2, & 3 rest on a horizontal frictionless surface, as shown. Each block has a mass m and the blocks are connected by massless strings. Block 3 is pulled to the right by a force F. The resultant force on block 2 is:
A
Zero
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B
(1/3)F
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C
(1/2)F
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D
(2/3)F
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Solution
The correct option is B (1/3)F According to the constraint of the system, all the three blocks will move with the same acceleration given by, a=F/(3∗m) Now, net force on second block will be equal to it's mass times acceleration. Feq2=m∗a=m∗(F/3m) Feq2=F/3