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Byju's Answer

Standard XII

Physics

Second Law of Motion

Three blocks ...

Question

Three blocks $A, B$ and $C$ are lying on a smooth horizontal surface, as shown in the figure. $A$ and $B$ have equal masses, $m$ while $C$ has mass $M$ . Block $A$ is given a brutal speed $v$ towards $B$ due to which it collides with $B$ perfectly inelastically. The combined mass collides with $C$ , also perfectly inelastically $\frac{5}{6} t h$ of the initial kinetic energy is lost in the whole process. What is the value of $\frac{M}{m}$ ?

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Solution

The correct option is A $4$

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The correct option is A 4

The correct option is A $4$