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Question

Three blocks A, B and C of masses 2 kg,3 kg and 4 kg are placed as shown. Coefficient of friction between A and B is 0.5 and that between B and C is 0.1. The surface is frictionless. The maximum force F in N that can be applied horizontally onto A such that the three blocks move together is (Answer upto 2 decimal places and take g=10 ms2
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Solution



Fs1=0.5×2×10=10 N
Fs2=5 N
Let acceleration of whole system be a
For C, then, ma=Fmaxs
a=54 m/s2
For B, a=54 m/s2
So, F=9×5/4=11.25 N

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