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Question

Three blocks A,B and C, of masses4kg,2kg and 1kg respectively are in contact on a friction less surface, as shown .if a force of 14N is applied on the 4kg blocks, then the contact force between A and B is
982235_92696ff0685b432392e3df1077720f9f.png

A
50N
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B
20N
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C
10N
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D
6N
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Solution

The correct option is D 6N
the acceleration due to force 14N,
F=ma
F/m =a
14/(4+2+1)
14/7
=2m/s2
the contact force between A and B is used to move the bodies B and C only.
F=ma
F=(2+1)2
F=3×2
=6N
Hence,
option $(D)$ is correct answer.

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