Three blocksA,B and C, of masses4kg,2kg and 1kg respectively are in contact on a friction less surface, as shown .if a force of 14N is applied on the 4kg blocks, then the contact force between A and B is
A
50N
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B
20N
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C
10N
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D
6N
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Solution
The correct option is D6N
the acceleration due to force 14N,
F=ma
F/m =a
14/(4+2+1)
14/7
=2m/s2
the contact force between A and B is used to move the bodies B and C only.