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Standard XII

Chemistry

Pressure and Temperature

Three blocks ...

Question

Three blocks are connected as shown in figure on a horizontal friction less table and pulled to the right with a force $T_{3} = 60 N$ . IF $m_{1} = 10 k g, m_{2} = 20 k g$ and $m_{3} = 30 k g$ , the tension $T_{2}$ is:

10 N

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20 N

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30 N

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60 N

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Solution

The correct option is C $30 N$
Total mass of the system = $m = m_{1} + m_{2} + m_{3}$ = 60 kg
$T_{2} = (m_{2} + m_{1}) a$
$T_{3} = (m_{3} + m_{2} + m_{1}) a$
So, $a = \frac{60}{60} = 1 m s^{- 2}$
$T_{2} = 30 \times 1 = 30 N$

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Three blocks are connected as shown in figure on a horizontal friction less table and pulled to the right with a force T3=60N. IF m1=10kg,m2=20kg and m3=30kg, the tension T2 is:

The correct option is C 30NTotal mass of the system = m=m1+m2+m3 = 60 kgT2=(m2+m1)aT3=(m3+m2+m1)aSo, a=6060=1ms−2T2=30×1=30N

Three blocks are connected as shown in figure on a horizontal friction less table and pulled to the right with a force $T_{3} = 60 N$ . IF $m_{1} = 10 k g, m_{2} = 20 k g$ and $m_{3} = 30 k g$ , the tension $T_{2}$ is:

The correct option is C $30 N$
Total mass of the system = $m = m_{1} + m_{2} + m_{3}$ = 60 kg
$T_{2} = (m_{2} + m_{1}) a$
$T_{3} = (m_{3} + m_{2} + m_{1}) a$
So, $a = \frac{60}{60} = 1 m s^{- 2}$
$T_{2} = 30 \times 1 = 30 N$