wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Three blocks are initially placed as shown in the figure. Block A has mass m and initial velocity V to the right. Block B with mass m and block C with mass 4 m are both initially at rest. Neglect friction. All collisions are elastic. The final velocity of block A is:

A
0.60 V to the left
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
1.4 V to the left
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
V to the left
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
0.4 V to the left
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A 0.60 V to the left
After 1st collision of A and B interchange their velocities (As collision is elastic and masses are equal),


Velocity of B
VB=mV+4m(0V)5m=3V5

After collision with C, B has velocity towards A.
So, after final collision of A and B velocity gets interchanged

VA=0.60 V to the left

flag
Suggest Corrections
thumbs-up
2
similar_icon
Similar questions
View More
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Basic Concepts
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon