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Impulsive Forces in Collision

Three blocks ...

Question

Three blocks of mass 1kg, 2kg and 3kg with coefficient of friction between the surfaces are as shown. The lock 2kg is connected to the spring.

The time period of oscillations of the three block system is

2 π

seconds

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π

seconds

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\frac{π}{2}

seconds

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3 π

seconds

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Solution

The correct option is B $π$ seconds

$F - f_{2} = (M_{1} + M_{2}) a f_{=} 12 N f_{3} = M_{3} a a = 4 m / s^{2} F - 12 = (1 + 2) 4 F = 24 N$
Maximum value for no slipping occurs
Kx =F
X =1m
$a = \frac{- K x}{6} a = - 4 x ω^{2} = \sqrt{4} T = \frac{2 π}{ω} = \frac{2 π}{\sqrt{4}} = π s e c o n d s$
F > 24 N; slipping occurs.

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Three blocks of mass 1kg, 2kg and 3kg with coefficient of friction between the surfaces are as shown. The lock 2kg is connected to the spring. The time period of oscillations of the three block system is

The correct option is B π seconds F−f2=(M1+M2)af=12Nf3=M3aa=4m/s2F−12=(1+2)4F=24N Maximum value for no slipping occurs Kx =F X =1m a=−Kx6a=−4xω2=√4T=2πω=2π√4=πseconds F > 24 N; slipping occurs.

Three blocks of mass 1kg, 2kg and 3kg with coefficient of friction between the surfaces are as shown. The lock 2kg is connected to the spring.

The time period of oscillations of the three block system is