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F=ma

Three blocks ...

Question

Three blocks of mass $3 k g, 2 k g$ and $1 k g$ are placed side by side on a smooth surface as shown in the figure. A horizontal force of $12 N$ is applied on $3 k g$ block. Find the net force in Newton, on $2 k g$ block.

4 N

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6 N

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12 N

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2 N

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Solution

The correct option is A $4 N$
As all the blocks are moving with same acceleration in horizontal direction .
So, we can consider it as a system.
so, $F_{n e t} = 12 N$
ALSO, $F_{n e t} = m a$
$12=(3+2+1)a
we get, $a = 2 m s^{- 2}$
so F at 2 kg = 2*2= 4N

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Three blocks of mass 3kg,2kg and 1kg are placed side by side on a smooth surface as shown in the figure. A horizontal force of 12N is applied on 3kg block. Find the net force in Newton, on 2kg block.

The correct option is A 4NAs all the blocks are moving with same acceleration in horizontal direction .So, we can consider it as a system.so, Fnet=12NALSO,Fnet=ma $12=(3+2+1)a we get, a=2ms−2so F at 2 kg = 2*2= 4N

Three blocks of mass $3 k g, 2 k g$ and $1 k g$ are placed side by side on a smooth surface as shown in the figure. A horizontal force of $12 N$ is applied on $3 k g$ block. Find the net force in Newton, on $2 k g$ block.

The correct option is A $4 N$
As all the blocks are moving with same acceleration in horizontal direction .
So, we can consider it as a system.
so, $F_{n e t} = 12 N$
ALSO, $F_{n e t} = m a$
$12=(3+2+1)a
we get, $a = 2 m s^{- 2}$
so F at 2 kg = 2*2= 4N