Three blocks of masses $2 k g, 3 k g$ and $5 k g$ are connected to each other with light string and are then placed on a frictionless surface as shown in the figure. The system is pulled by a force $F = 10 N$ , then tension $T_{1}$ :

1 N

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5 N

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8 N

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10 N

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Solution

The correct option is D $8 N$
We have $T_{1} = \frac{(m_{2} + m_{3}) F}{m_{1} + m_{2} + m_{3}}$
$T_{1} = 8 N$

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Similar questions

Q. Three blocks of masses

2 k g, 3 k g

and

5 k g

are connected to each other with light string and are then placed on a frictionless surface as shown in the figure. The system is pulled by a force

F = 10 N

, then tension

T_{1} =

Three blocks of masses 2 kg, 3 kg and 5 kg are connected to each other with light string and are then placed on a frictionless surface as shown in the figure. The system is pulled by a force F = 10 N,, then tension $T_{1} =$

Q. Three blocks of mass

2 k g

3 k g

and

5 k g

are connected to each other with light string and are then placed on a frictionless surface as shown in the figure. The system is pulled by a force of

10 N

, tension

T_{1}

is equal to

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Three blocks of masses 2kg,3kg and 5kg are connected to each other with light string and are then placed on a frictionless surface as shown in the figure. The system is pulled by a force F=10N, then tension T1 :

The correct option is D 8NWe have T1=(m2+m3)Fm1+m2+m3T1=8N

Three blocks of masses $2 k g, 3 k g$ and $5 k g$ are connected to each other with light string and are then placed on a frictionless surface as shown in the figure. The system is pulled by a force $F = 10 N$ , then tension $T_{1}$ :

The correct option is D $8 N$
We have $T_{1} = \frac{(m_{2} + m_{3}) F}{m_{1} + m_{2} + m_{3}}$
$T_{1} = 8 N$