Three blocks P,Q and R of masses 5 kg,4 kg respectively are connected by a light inextensibile string and they are moved on a smooth horizontal plane. If a force of 24 N is applied to the string connected to R, tensions T1 and T2 in the string are:
Given that,
Force F=24N
Mass of P=5kg
Mass of Q=4kg
Mass of R=3kg
Now, the acceleration is
F=ma
24=(5+4+3)a
a=2412
a=2m/s2
According to FBD
Now, the tension is
24−T1=3a
24−T1=6
T1=18N
Now, again
T1−T2=4a
18−T2=8
T2=10N
Hence, the tension is T1=18N and T2=10N