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Question

Three blocks a, b and c of masses 10 kg, 10 kg and 20 kg respectively are arranged as shown in figure. All the surfaces are frictionless and string is inextensible. A constant force F=20 N is applied on block a as shown. Pulley and string are light. Part of the string connecting both pulleys is vertical and part of the strings connecting pulleys with masses a and b are horizontal. Choose the correct option(s) for the given system.


A
Acceleration of block b is 0.5 m/s2
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B
Acceleration of block b is 1 m/s2
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C
Tension in the string is 10 N
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D
Acceleration of block c is 0.5 m/s2
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Solution

The correct option is C Tension in the string is 10 N
Block c will remain stationary because external forces on it balance each other. Hence block c won't accelerate.

Due to string constraint,
Acceleration of a = acceleration of b
=Fma+mb=2010+10=1 m/s2
Tension, T=mb× (acceleration of b)
T=(10)(1)=10 N

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