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Horizontal and Vertical Components of Projectile Motion

Three bodies ...

Question

Three bodies are projected in three different ways: a) vertically up b) vertically down c) horizontally, with same speed from top of a tower. The time taken by the bodies to reach the ground in increasing order would be:

A

t_{b} < t_{a} < t_{c}

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B

t_{c} < t_{a} < t_{b}

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C

t_{b} < t_{c} < t_{a}

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D

t_{a} < t_{b} < t_{c}

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Solution

The correct option is C $t_{b} < t_{c} < t_{a}$
a) $s = u t_{a} - \frac{1}{2} g t_{a}^{2}$
b) $s = u t_{b} + \frac{1}{2} g t_{b}^{2}$
c) $s = 0 \times t_{c} + \frac{1}{2} g t_{c}^{2}$
For c) we have put $u = 0$ since vertical component of initial velocity is zero.
Clearly $t_{a} > t_{c} > t_{b}$

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Horizontal and Vertical Components of Projectile Motion

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