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Question
Three boys and four girls stand in queue for an interview. The probability that they stand in alternate positions is:
Three boys and four girls stand in queue for an interview. The probability that they stand in alternate positions is:
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Solution
The correct option is A ()
Total number of possible arrangements for 3 boys and 4 girls in a queue = 7!
When they occupy alternate positions, the arrangement would be like:
G B G B G B G
Thus, total number of possible arrangements for girls = 4!
Total number of possible arrangements for boys = 3!
Required probability = 4!3!7! = 135
()
Total number of possible arrangements for 3 boys and 4 girls in a queue = 7!
When they occupy alternate positions, the arrangement would be like:
G B G B G B G
Thus, total number of possible arrangements for girls = 4!
Total number of possible arrangements for boys = 3!
Required probability = 4!3!7! = 135
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