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Question

Three boys and four girls stand in queue for an interview. The probability that they stand in alternate positions is:


A

()

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B

()

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C

()

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D

()

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Solution

The correct option is A

()


Total number of possible arrangements for 3 boys and 4 girls in a queue = 7!

When they occupy alternate positions, the arrangement would be like:

G B G B G B G

Thus, total number of possible arrangements for girls = 4!

Total number of possible arrangements for boys = 3!

Required probability = 4!3!7! = 135


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