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Question

Three brands A, B and C of biscuits are available in packets of 12, 15, and 21 biscuits respectively.
If a shopkeeper wants to buy an equal number of biscuits of each brand, then what is the minimum number of packets of each brand he should buy? [4 MARKS]

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Solution

Formula: 1 Mark
Steps: 2 Marks
Answer: 1 Mark

For a minimum number of biscuits, first, we find the LCM of 12, 15 and 21.
The prime factors of the following numbers are:
12=2×2×3
15=3×5
21=3×7
The maximum number of times the prime factor 2 occurs is 2.
The maximum number of times the prime factor 3 occurs is 1.
The maximum number of times the prime factor 5 occurs is 1.
The maximum number of times the prime factor 7 occurs is 1.
LCM= 3 × 4 × 5 × 7 = 420
Minimum number of packets of brand A =42012=35
Minimum number of packets of brand B =42015=28
And minimum number of packets of brand C =42021=20

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Number of packets of biscuits sold by the shopkeeper (in the year ending on 31st March 2010):
Month Number of packets sold (in hundreds)
April 73
May 74
June 76
July 86
August 88
September 88
October 89
November 90
December 90
January 105
February 110
March 115

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