Three bulbs with individual power ratings of $12 W, 2 W$ and $6 W$ respectively are connected as per the circuit diagram. Find the amount of heat dissipated by each in 10 seconds.

12 W - 144 J, 2 W - 20 J, 6 W - 60 J

No worries! We‘ve got your back. Try BYJU‘S free classes today!

12 W - 120 J, 2 W - 24 J, 6 W - 60 J

No worries! We‘ve got your back. Try BYJU‘S free classes today!

12 W - 120 J, 2 W - 20 J, 6 W - 72 J

No worries! We‘ve got your back. Try BYJU‘S free classes today!

12 W - 120 J, 2 W - 20 J, 6 W - 60 J

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is B $12 W - 120 J, 2 W - 20 J, 6 W - 60 J$
As the three bulbs are connected in parallel, thus the voltage across each bulb is same i.e. $V = 12$ volts.
Heat dissipated $H = P t$
Heat dissipated in $12$ watt bulb $H_{1} = 12 \times 10 = 120 J$
Heat dissipated in $2$ watt bulb $H_{2} = 2 \times 10 = 20 J$
Heat dissipated in $6$ watt bulb $H_{3} = 6 \times 10 = 60 J$

Suggest Corrections

Similar questions

(3 + 3 w + 5 w^{2})^{6} - (2 + 6 w + 2 w^{2})^{3} = 0

C_{1} a n d C_{2}

C_{1} a n d C_{2}

C_{1} a n d C_{2}

△ U

10^{- 12} W / m^{2}

10^{- 6} W / m^{2}

Join BYJU'S Learning Program