Question

Three canisters $A,B,$ and $C$ are all at the same temperature, with volumes of $2.0,4.0,$ and $6.0L$, respectively. Canister $A$ contains 0.976 g $Ar$ at 120 torr, canister $B$ contains 1.37 g $N_2$ at 120 torr, and canister $C$ is completely empty at the start. Assuming ideally, what would be the pressure in canister $C$ if the contents of $A$ and $B$ are completely transferred to $C$?

• A. 180 torr
• B. 330 torr
• C. 675 torr
• D. 0.25 atm
• E. none of the above

Answer 1

The correct option is E none of the above

After transferring, $n_C$$=$$n_A+n_B$

So, using ideal gas law, $PV$$=$$nRT$

Temperature $T$ is same in all three vessels, hence

$P_C{V}_C$$=$$P_A{V}_A+P_B{V}_B$

So, $P_C$$=$$(120\times 2+120\times 4)/6$$=$$120torr$