Question

Three cans contain $12L,16L$ and $24L$ of milk. A mug is filled with a whole number of times from each can. What is the greatest capacity of the mug?

Answer 1

We have to calculate the HCF:
$\begin{array}{rcl}12& =& 2\times 2\times 3\\ 16& =& 2\times 2\times 2\times 2\\ 24& =& 2\times 2\times 2\times 3\end{array}$
$$\begin{gathered} Commonfactor=2\times 2=4 \\ HCF=4 \end{gathered}$$
Hence, $4L$ is the greatest capacity of the mug.