Question

Three cans contain 23.265 ml, 60.5 ml and 71.486 ml of kerosene. What should be the minimum capacity of a can that can hold the total quantity of kerosene rounded off to 2 decimal places?

• A. 155.251 ml
• B. 155.50 ml
• C. 155.21 ml
• D. 155.25 ml

Answer 1

The correct option is D

155.25 ml

All the units of measurement are same. After converting the numbers to like decimals, we can add all three quantities.

$23.265$
$+60.500$
$+71.486$
$\overline{}$
$155.251ml$
$\overline{}$

Rounding off to two decimal places we get 155.25 ml which is the minimum capacity that the can should have.