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Standard XII

Physics

Parallel and Series Combination of Capacitors

Three capacit...

Question

Three capacitors are connected as shown in figure. Then the charge on capacitor $C_{1}$ is

6 μ C

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12 μ C

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18 μ C

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24 μ C

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Solution

The correct option is A $6 μ C$
Charge supplied both the batteries would be same say $q$ .

Thus charge on the $4 μ F$ capacitor would be 2q (by law of conservation of charge)

Thus using loop rule we get

$6 = \frac{q}{2} + \frac{2 q}{4}$
or
$q = 6 μ C$

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Three capacitors are connected as shown in figure. Then the charge on capacitor C1 is

The correct option is A 6μCCharge supplied both the batteries would be same say q.Thus charge on the 4μF capacitor would be 2q (by law of conservation of charge)Thus using loop rule we get6=q2+2q4orq=6μC

Three capacitors are connected as shown in figure. Then the charge on capacitor $C_{1}$ is

The correct option is A $6 μ C$
Charge supplied both the batteries would be same say $q$ .

Thus charge on the $4 μ F$ capacitor would be 2q (by law of conservation of charge)

Thus using loop rule we get

$6 = \frac{q}{2} + \frac{2 q}{4}$
or
$q = 6 μ C$