Three capacitors are connected as shown in figure. Then the charge on capacitor plate $C_{1}$ is:

6 $μ C$

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12 $12 μ C$

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18 $μ C$

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24 $μ C$

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Solution

The correct option is A
6 $μ C$

Potential D = 0

Let potential at B = x

Potential at A = 6V

Potential at C = 6V

By conservation of charge

$\Rightarrow x = 3 V$

Charge on $C_{1} = (6 - 3) 2 = 6 μ C$

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