Question

Three capacitors are connected as shown in figure. Then the charge on capacitor plate $C_1$ is:

• A. $6\mu C$
• B. $12\mu C$
• C. $18\mu C$
• D. $24\mu C$

Answer 1

The correct option is A $6\mu C$


The summation of charge all the three capacitors is zero.
If $x$ is the potential of the junction connecting all three capacitors, we can write
$(x-6)2+(x-6)2+x\times 4=0x=3V{q}_{C_1}=2\times 3=6\mu C$