Question

Three capacitors are connected in the arms of a triangle ABC as shown in the figure. 5V voltage is applied between A and B. The voltage between B and C is:

• A. 2V
• B. 1V
• C. 1.5V
• D. 0.5V

Answer 1

The correct option is A 2V

From the figure we can write
$V_{BC}=\frac{2}{2+3}.5$
$=\frac{2}{5}\times 5=2V$

Hence the voltage across the BC is 2 V.