Question

Three capacitors $C_1=6\mu F,C_2=12\mu F$ and $C_3=20\mu F$ are connected to a $100V$ battery, as shown following figure below:
Calculate:
Charge on each plate of capacitor $C_1$

Answer 1

$\frac{1}{C_1^{\prime }}=\frac{1}{6}+\frac{1}{12}$

$\frac{1}{C_1^{\prime }}=\frac{2+1}{12}=\frac{3}{12}=\frac{1}{4}$

$C_1^{\prime }=4\mu F$

$C_{eq}=C_1^{\prime }+C_3$

$C_{eq}=4+20=24\mu F$

$q=CV=24\times {10}^{-6}\times 100$

$q=24\times {10}^{-4}coulomb$

$q=CV$

$q=6\times {10}^{-6}\times 100$
$=600\times {10}^{-6}=600\mu coulomb$