Three capacitors each of capacity 4μF are to be connected in such a way that we get the effective capacitance of 6μF. This can be done by:
A
connecting all of them in series
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B
connecting them in parallel
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C
connecting two in series and one in parallel
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D
connecting two in parallel and one in series
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Solution
The correct option is C connecting two in series and one in parallel To get equivalent capacitance 6μF two 4μF capacitors are
to be connected in series and third one is connected in parallel. From figure equivalent capacitance Ceq=4×44+4+4=2+4=6μF