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Question

Three capacitors each of capacity 4μF are to be connected in such a way that we get the effective capacitance of 6μF. This can be done by:

A
connecting all of them in series
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B
connecting them in parallel
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C
connecting two in series and one in parallel
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D
connecting two in parallel and one in series
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Solution

The correct option is C connecting two in series and one in parallel
To get equivalent capacitance 6μF two 4μF capacitors are to be connected in series and third one is connected in parallel.
From figure equivalent capacitance
Ceq=4×44+4+4=2+4=6μF
1016207_69491_ans_7f022bb86fd2493a93cd62856f9741b8.PNG

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