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Question

Three capacitors of capacitance 3 μF, 10 μF and 15 μF are connected in series to a battery of 100 V. The charge on 15 μF is

A
200 μC
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B
50 μC
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C
280 μC
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D
100 μC
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Solution

The correct option is A 200 μC
In series combination, the equivalent capacitance is given by

1Ceq=1C1+1C2+1C3

1Ceq=13+110+115=12

Ceq=2 μF

Moreover, in a series combination, the charge on each capacitor is the same, which is the same as the charge on the equivalent capacitor.

Now using Q=CV, we get

Q=2μF×100V=200μC

Hence, option (c) is correct.
Key Concept : Charge on a capacitor in a series arrangement in a circuit.


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