Three capacitors of capacitance $6 μ F$ each are available. The minimum and maximum capacitance which may be obtained are

$6 μ F, 18 μ F$

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$3 μ F, 12 μ F$

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$2 μ F, 12 μ F$

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$2 μ F, 18 μ F$

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Solution

The correct option is D
$2 μ F, 18 μ F$

$C_{m a x} = 3 \times 6 μ F = 18 μ F C_{m i n} = \frac{6}{3} μ F = 2 μ F$

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