Question

Three capacitors of capacitances $4\mu F,6\mu F$ and $8\mu F$ are connected in parallel.
(i) What is the ratio of charges?
(ii) What is the ratio of potential differnces?

Answer 1

(ii) : Potential difference is same across the electrical components which are connected in parallel to each other.

Thus potential difference across the three capacitors is same (or equal), hence ratio of potential differences is $1:1:1$.

(i) : Given: $C_1=4\mu F$ $C_2=6\mu F$ $C_3=8\mu F$

Charge on capacitor, $Q=CV$

$⟹$ $Q\propto C$ (as $V$ is same across the capacitors)

Thus ratio of charges $Q_1:Q_2:Q_3=C_1:C_2:C_3$

$\therefore$ $Q_1:Q_2:Q_3=4:6:8$

$⟹$ $Q_1:Q_2:Q_3=2:3:4$