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Standard XII

Physics

Kirchhoff's Junction Law

Three capacit...

Question

Three capacitors of capcitances $3 μ F$ , $4 μ F$ and $6 μ F$ are charged upto a potential difference of $2 V, 3 V$ and $4 V$ respectively. If terminal $a$ is connected with $f,$ terminal $e$ is connected with $d$ and $c$ is connected with $b$ then find the charge flowing through the circuit?

24 μ C

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12 μ C

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16 μ C

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9 μ C

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Solution

The correct option is B $12 μ C$
According to the problem:

Let $q$ amount of charge flow in the circuit,

Applying $KVL$ , to the loop $RSQP$ ,

$\frac{24 - q}{6} + \frac{12 - q}{4} + \frac{6 - q}{3} = 0$

$\Rightarrow 48 - 2 q + 36 - 3 q + 24 - 4 q = 0$

$\Rightarrow 108 = 9 q$

$∴ q = 12 μ C$

Hence, option (b) is correct answer.

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Kirchhoff's Junction Law

Standard XII Physics

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Three capacitors of capcitances 3 μF, 4 μF and 6 μF are charged upto a potential difference of 2V, 3V and 4V respectively. If terminal a is connected with f, terminal e is connected with d and c is connected with b then find the charge flowing through the circuit?

The correct option is B 12 μCAccording to the problem: Let q amount of charge flow in the circuit, Applying KVL, to the loop RSQP, 24−q6+12−q4+6−q3=0 ⇒48−2q+36−3q+24−4q=0 ⇒108=9q ∴q=12 μC Hence, option (b) is correct answer.

Three capacitors of capcitances $3 μ F$ , $4 μ F$ and $6 μ F$ are charged upto a potential difference of $2 V, 3 V$ and $4 V$ respectively. If terminal $a$ is connected with $f,$ terminal $e$ is connected with $d$ and $c$ is connected with $b$ then find the charge flowing through the circuit?