Question

Three capacitors of capcitances $3\mu \text{F}$, $4\mu \text{F}$ and $6\mu \text{F}$ are charged upto a potential difference of $2V,3V$ and $4V$ respectively. If terminal $\text{a}$ is connected with $\text{f,}$ terminal $\text{e}$ is connected with $\text{d}$ and $\text{c}$ is connected with $\text{b}$ then find the charge flowing through the circuit?

• A. $24\mu \text{C}$
• B. $12\mu \text{C}$
• C. $16\mu \text{C}$
  
• D. $9\mu \text{C}$
  

Answer 1

The correct option is B $12\mu \text{C}$

According to the problem:


Let $q$ amount of charge flow in the circuit,


Applying $\text{KVL}$, to the loop $\text{RSQP}$,

$\frac{24-q}{6}+\frac{12-q}{4}+\frac{6-q}{3}=0$

$\Rightarrow 48-2q+36-3q+24-4q=0$

$\Rightarrow 108=9q$

$\therefore q=12\mu \text{C}$

Hence, option (b) is correct answer.