Three cards are drawn with replacement from a well shuffled pack of cards. Find the probability that the cards drawn are king, queen and jack.

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Solution

$P (king) = \frac{4}{52} P (queen) = \frac{4}{52} P (jack) = \frac{4}{52} These cards can be drawn in^{3} P_{3} ways . P (king, queen and jack) = \frac{4}{52} \times \frac{4}{52} \times \frac{4}{52} \times^{3} P_{3} = \frac{3!}{2197} = \frac{6}{2197}$

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Three cards are drawn with replacement from a well shuffled pack of cards. Find the probability that the cards drawn are king, queen and jack.

Pking=452Pqueen=452Pjack=452These cards can be drawn in 3P3 ways.Pking, queen and jack=452×452×452×3P3=3!2197=62197

$P (king) = \frac{4}{52} P (queen) = \frac{4}{52} P (jack) = \frac{4}{52} These cards can be drawn in^{3} P_{3} ways . P (king, queen and jack) = \frac{4}{52} \times \frac{4}{52} \times \frac{4}{52} \times^{3} P_{3} = \frac{3!}{2197} = \frac{6}{2197}$