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Standard XII

Physics

Newton's Law of Gravitation

Three charge ...

Question

Three charge +4q, Q and q are placed in a straight line of length l at points distance 0, l/2 and l respectively. What should be the value of Q in order to make the net force on q to be zero?

-q

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-q/2

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Solution

The correct option is A -q
$F_{C} = 0$
$F_{C} = F_{A} C + F_{A} B$
$⟹ 0 = k \frac{{4 q}^{2}}{(1)^{2}} + k \frac{Q_{2}}{({\frac{1}{2})}^{2}}$
$= k [4 q^{2} + 4 Q q^{2}]$
$⟹ 0 = 4 q^{2} + 4 Q q$
$⟹ 0 = 4 q [q + Q]$
$⟹ q + Q = 0$
$⟹ Q = - q$

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Three charge +4q, Q and q are placed in a straight line of length l at points distance 0, l/2 and l respectively. What should be the value of Q in order to make the net force on q to be zero?

The correct option is A -qFC=0FC=FAC+FAB⟹0=k4q2(1)2+kQ2(12)2 =k[4q2+4Qq2]⟹0=4q2+4Qq⟹0=4q[q+Q]⟹q+Q=0⟹Q=−q

The correct option is A -q
$F_{C} = 0$
$F_{C} = F_{A} C + F_{A} B$
$⟹ 0 = k \frac{{4 q}^{2}}{(1)^{2}} + k \frac{Q_{2}}{({\frac{1}{2})}^{2}}$
$= k [4 q^{2} + 4 Q q^{2}]$
$⟹ 0 = 4 q^{2} + 4 Q q$
$⟹ 0 = 4 q [q + Q]$
$⟹ q + Q = 0$
$⟹ Q = - q$