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Standard XII
Physics
Introducing Flux
Three charged...
Question
Three charged particles having charges q, -2q and q are placed in a line at points (-a,0), (0,0) and (a,0) respectively. Find the expression for electric potential at P(r,0) for r > a.
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Solution
V
=
k
q
(
r
+
a
)
+
k
(
−
2
q
)
r
+
k
q
(
r
−
a
)
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Similar questions
Q.
Three charged particles having charges q, -2q & q are placed in a line at points (-a, 0), (0, 0) & (a, 0) respectively. The expression for electric potential at P(r, 0) for r > > a is
Q.
Three point charges
+
q
,
−
2
q
and
+
q
are placed at
(
x
=
0
,
y
=
a
,
z
=
0
)
,
(
x
=
0
,
y
=
0
,
z
=
0
)
and
(
x
=
a
,
y
=
0
,
z
=
0
)
respectively. The magnitude and direction of the electric dipole moment vector for the given system of charges are
Q.
Three points charges
+
q
,
−
2
q
and
+
q
are placed at points
(
0
,
1
,
0
)
,
(
0
,
0
,
0
)
and
(
1
,
0
,
0
)
respectively. The magnitude and direction of the resultant electric dipole moment vector of this charge assembly will be :
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Three point charges
+
q
,
−
2
q
and
+
q
are placed at points
(
x
=
0
,
y
=
a
,
z
=
0
)
,
(
x
=
0
,
y
=
0
,
z
=
0
)
and
(
x
=
a
,
y
=
0
,
z
=
0
)
respectively. The magnitude and direction of the electric dipole moment vector of this charge assembly are:
Q.
Three point charges +q, -2q and +q are placed at point (x =0,y=a, z=0),(x = 0, y=0, z=0) and (x=a, y =0, z =0) respectively. The magnitude and direction of the electric dipole moment vector of this charge assembly are :
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