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Question

Three charges 1μC,2μC, and 3μC are kept at vertices of an equilateral triangle of side 1 m. If they are brought nearer, so that they now form an equilateral triangle of side 0.5m, then work done is :

A
0.11J
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B
11J
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C
0.01J
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D
1.1J
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Solution

The correct option is C 0.01J
Initial PE of the three charges,
U1=kq1q2+q2q3+q1q3r
=9×109[1×2×1012+2×3×1012+1×3×10121]
=99×103J

Final PE of the system

Uf=9×109[1×2×1012+2×3×1012+1×3×10120.5]
=99×1030.5=198×103J
W=UfUi=(19899)×103J
=99×103J
=0.099=0.01J

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