Three charges -4Q-Q and q is placed in a straight line of lenth l at points 0-1 - 2 and 1 distance away from one end respectively-What should be Q in order to make the net force on q to be zero-

two force are acting on q ,one due to 4q and second due to Q F1 = 1/4∏ε (4q)q/l2 F2 = 1/4∏ε (Q)q/(l/2)2 = 1/4∏ε (4Q)q/l2 F1 +F2 =0 1/4∏ε (4q)q/l2 ...

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Standard XII

Physics

Coulomb's Law - Vector Form

Three charges...

Question

Three charges +4Q,Q and q is placed in a straight line of lenth l at points 0,l/2and l distance away from one end respectively.What should be Q in order to make the net force on q to be zero?

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Solution

two force are acting on q ,one due to 4q and second due to Q

F1 = 1/4∏ε (4q)q/l²

F2 = 1/4∏ε (Q)q/(l/2)²

= 1/4∏ε (4Q)q/l²

F1 +F2 =0

1/4∏ε (4q)q/l²+ 1/4∏ε (4Q)q/l²=0

Q=-q

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Three charges +4Q,Q and q is placed in a straight line of lenth l at points 0,l/2and l distance away from one end respectively.What should be Q in order to make the net force on q to be zero?

two force are acting on q ,one due to 4q and second due to Q F1 = 1/4∏ε (4q)q/l2 F2 = 1/4∏ε (Q)q/(l/2)2 = 1/4∏ε (4Q)q/l2 F1 +F2 =0 1/4∏ε (4q)q/l2 + 1/4∏ε (4Q)q/l2 =0 Q=-q

two force are acting on q ,one due to 4q and second due to Q

F1 = 1/4∏ε (4q)q/l²

F2 = 1/4∏ε (Q)q/(l/2)²

= 1/4∏ε (4Q)q/l²

F1 +F2 =0

1/4∏ε (4q)q/l²+ 1/4∏ε (4Q)q/l²=0

Q=-q