Three charges each of charge ‘q’ are placed at the corners of an equilateral triangle. The fourth charge to be placed at the centre of the triangle so that electrostatic potential energy of the system is zero is

\frac{q}{\sqrt{3}}

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\frac{- q}{\sqrt{3}}

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q

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\frac{- q}{\sqrt{2}}

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Solution

The correct option is B $\frac{- q}{\sqrt{3}}$
PE=0
$3 \frac{1}{4 π ϵ_{0}} \frac{q^{2}}{a} + 3 \frac{1}{4 π ϵ_{0}} \times \frac{q x}{(\frac{a}{\sqrt{3}})} = 0 \sqrt{3} x = - q x = - \frac{q}{\sqrt{3}}$

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Three charges each of charge ‘q’ are placed at the corners of an equilateral triangle. The fourth charge to be placed at the centre of the triangle so that electrostatic potential energy of the system is zero is

The correct option is B −q√3PE=0 314πϵ0q2a+314πϵ0×qx(a√3)=0√3x=−qx=−q√3

The correct option is B $\frac{- q}{\sqrt{3}}$
PE=0
$3 \frac{1}{4 π ϵ_{0}} \frac{q^{2}}{a} + 3 \frac{1}{4 π ϵ_{0}} \times \frac{q x}{(\frac{a}{\sqrt{3}})} = 0 \sqrt{3} x = - q x = - \frac{q}{\sqrt{3}}$