Potential Energy of a System of Multiple Point Charges
Three charges...
Question
Three charges Q + q and +q are placed at the vertices of a right-angled isosceles triangle as shown. The net electrostatic energy of the configuration is zero if Q is equal to
A
−q1+√2
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B
−2q2+√2
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C
−2q
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D
+q
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Solution
The correct option is B−2q2+√2
Net electrostatic energy U=kQqa+kq2a+kQqa√2=0 ⇒kqa(Q+q+Q√2)=0⇒−2q2+√2