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Question

Three circles are placed on a plane in such a way that each circle just touches the other two, each having a radius of 10 cm. Find the area of region enclosed by them.

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Solution

Let there be 3 circles with centre A, B and C respectively such that each circle touches the other two. They all have radius of 10 cm.

We have to find the area enclosed between the circles.

We have,


AB = 10 + 10 cm = 20 cm
BC = 10 + 10 cm = 20 cm
CA = 10 + 10 cm = 20 cm

Henceis an equilateral triangle.

So,,

So, the area enclosed between the circles,

So,

Put the values to get,


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